What is the Empirical Formula of the Phosphorus Selenide? Speeli
What Is The Empirical Formula Of Phosphorus Selenide. A 1.45 − g sample of phosphorus. Web a sample of 45.2 mg of phosphorus reacts with selenium to form 131.6 mg of selenide.
A 1.45 − g sample of phosphorus. Web so the empirical formula of the phosphorus selenide is p3se2. Determine the empirical formula of phosphorus selenide. Also, why are people attracted to sunsets? Atomic mass of selenium = 79g. 45.2/31 = 1.45 which is nearly 1.5 mol of p. A 43.4 the empirical formula is p4 4 se3 3. What is the empirical formula of the phosphorus selenide? First we need the masses of each element in the. What is the empirical formula of phosphorus selenide express your answer as a chemical formula?
1 see answer advertisement w0lf93 atomic mass of phosphorous = 31g atomic mass of selenium = 79g. What is the empirical formula of the phosphorus selenide?. Atomic mass of selenium = 79g. The molecular formula shows the composition of the molecules. Determine the empirical formula of phosphorus selenide. Atomic mass of phosphorous = 31g. Web an empirical formula is one that shows the lowest whole number ratio of the elements present. Web the empirical formula of phosphorus selenide is p4 se3. Web so the empirical formula of the phosphorus selenide is p3se2. Also, why are people attracted to sunsets? Atomic mass of phosphorus = 31g atomic mass of selenium = 79g 45.2/31 =.
